# Particle A moves along X-axis with a uniform velocity of magnitude 10 m/s. Particle B moves with uniform velocity 20 m/s along a direction making an angle of 60° with the positive direction of X-axis as shown in the figure. The relative velocity of B with respect to that A is

10 m/s along X-axis

10√3 m/s along Y-axis (perpendicular to X-axis)

10√5along the bisection of the velocity of A and B

30 m/s along negative X-axis

## The correct Answer is:B

## −−→VBA=→VB−→VA

=(20×cos60∘ˆi+20sin60∘ˆj)−10ˆi=10√3ˆj

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